ae^x=1+x+x^2/2!

[kinu]

The no. of real solution of the equation \(ae^x = 1+x+\frac{x^2}{2!}\)

where \(a>0\)

[João P. Ferreira]

It has one solution, and that solution will depend on \(a\)

Check this

And please kinu, be more moderate with the number of posting exercices.

We're not exercices solving machines...