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| ae^x=1+x+x^2/2! https://forumdematematica.org/viewtopic.php?f=15&t=189 |
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| Autor: | kinu [ 06 fev 2012, 18:10 ] |
| Título da Pergunta: | ae^x=1+x+x^2/2! |
The no. of real solution of the equation \(ae^x = 1+x+\frac{x^2}{2!}\) where \(a>0\) |
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| Autor: | João P. Ferreira [ 07 fev 2012, 17:05 ] |
| Título da Pergunta: | Re: ae^x = 1+x+\frac{x^2}{2!} |
It has one solution, and that solution will depend on \(a\) Check this And please kinu, be more moderate with the number of posting exercices. We're not exercices solving machines... |
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