Fórum de Matemática
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\(\int_{0}^{2}(10-3q)dq/(q+2)\)

\((i)\frac{10-3q}{q+2}=-3+\frac{16}{q+2}\)

\((ii)\int_{0}^{2}(\frac{10-3q}{q+2})dq=\int_{0}^{2}\left ( -3+\frac{16}{q+2} \right )dq=\int_{0}^{2}-3dq+\int_{0}^{2}\left ( \frac{16}{q+2} \right )dq\)

\(-3q{|_{0}}^{2} + 16ln(q+2){|_{0}}^{2}=-3(2-0)+16(ln4-ln2)=-6+16ln2\)

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