Todas as dúvidas que tenha sobre arranjos simples, completos, combinações ou probabilidades
17 mar 2016, 03:02
1) Dado P (A) = 1/2;P (B) = 1/3, P (A ∩ B) = 1/4, calcular:
a) P (A ∪ B);
b) P (A/B)
c) P (B/A);
d) P[A∪B) /B]
17 mar 2016, 10:07
\(P(A \cup B)=P(A)+P(B)-P(A\cap B)= \frac 12 + \frac 13-\frac 14 = \frac{7}{12}\)
\(P(A/B)= P(A)-P(A\cap B) = \frac 12 \frac 14 = \frac 14\)
\(P(B/A) = P(B)-P(A\cap B)=\frac 13 - \frac 14 = \frac{1}{12}\)
\(P((A \cup B)/B) = P(A)=\frac 12\)
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