solucionar expressão trigonométrica com arctan

[miguel.silva]

\(\tan^{-1}(2+\tan (3\pi /4))\)
obrigado

[pedrodaniel10]

\(\tan^{-1}(2+\tan (3\pi /4))=\tan^{-1}(2-1)=\tan^{-1}(1)=\frac{\pi}{4}\)

[jorgeluis]

\(tan^{-1}(2+tan \frac{3\pi}{4}) =\)

fazendo:
\(\theta = tan^{-1}(2+tan \frac{3\pi}{4})\)
se,
\(tan \frac{3\pi}{4} = -tan (\pi-\frac{3\pi}{4})
tan \frac{3\pi}{4} = -tan \frac{\pi}{4}\)
e,
\(tan \frac{\pi}{4} = 1\)
então,
\(\theta = tan^{-1}(2-1)\)
\(\theta = tan^{-1} 1\)
ou
\(tan \theta = 1
\theta=45^o\)