calculo de integrais primitivas calculo 1

[gerlanmatfis]

\(\large \int (3x-1)dx\)


\(\int (x^3+2x+3)dx\)

[danko71]

\(\int (3x-1)dx=\frac{3x^2}{2}-x+C\)

Outra maneira:
\(\int (3x-1)dx=3\int xdx-\int dx=\frac{3x^2}{2}-x+C\)

Exercício 2
\(\int (x^3+2x+3)dx=\frac{x^4}{4}+\frac{2x^2}{2}+3x=\frac{1}{4}x^4+x^2+3x+C\)