limites
26 set 2013, 03:37
calcule o limite:
\(\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{x^2-9}\)
\(\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{x^2-9}\)
Editado pela última vez por Man Utd em 26 set 2013, 15:31, num total de 1 vez.
Razão: Arrumar o Latex
Razão: Arrumar o Latex
Re: limites
26 set 2013, 15:30
olá 
\(\\\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{x^{2}-9} \\\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2x+6-12}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2x-6}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2(x-3)}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2}{x+3}=\frac{1}{3}\)
att mais
\(\\\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{x^{2}-9} \\\\\\ \lim_{x\rightarrow 3} \frac{2}{x-3}-\frac{12}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2x+6-12}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2x-6}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2(x-3)}{(x-3)*(x+3)} \\\\\\ \lim_{x\rightarrow 3} \frac{2}{x+3}=\frac{1}{3}\)
att mais