Coloque aqui todas as dúvidas que tiver sobre limites, regra de Cauchy ou L'Hopital, limites notáveis e afins
05 fev 2014, 12:41
favor resolver para mim:
Limx → 7 ((X + 2)1/2 – 3)/(x – 7)
05 fev 2014, 14:49
usando l'hopital
\(\lim_{x_\to{7}}\frac{\frac{(x+2)}{2}-3}{x-7}=\lim_{x_\to{7}}\frac{\frac{(x+2)-6}{2}}{(x-7)}=\lim_{x_\to{7}}\frac{(x-4)'}{2(x-7)'}=\lim_{x_\to{7}}\frac{1}{2}=\frac{1}{2}\)
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