26 jan 2014, 16:01
Sabendo que a+b=9 e que a.b= 20 calcule
a)\(a^2 + b^2\)
b)\((a-b)^2\)
respostas são 41 e 121
26 jan 2014, 16:45
a) a²+b² = (a+b)²-2ab
a²+b² = 9² - 2.20 = 81-40 = 41
b) Minha resposta nao esta dando 121
(a-b)² = (a+b)²-4ab = 9²-4.20 = 81-80 = 1
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