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| Integer solution https://forumdematematica.org/viewtopic.php?f=70&t=230 |
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| Autor: | kinu [ 12 mar 2012, 07:22 ] |
| Título da Pergunta: | Integer solution |
find all integer value of \(a\) for which the equation \(x^2+ax+6a=0\) has Integer solution |
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| Autor: | Rui Carpentier [ 12 mar 2012, 16:19 ] |
| Título da Pergunta: | Re: Integer solution |
Hint: \(x^2+ax+6=0\Leftrightarrow a=\frac{-x^2}{x+6}\Leftrightarrow a=-x+6-\frac{36}{x+6}\). Thus \(a\) is integer if and only if \(x+6\) divides \(36\). All you have to do now is to solve the equation \(x+6=d\) for all eighteen interger divisors \(d\) of \(36\), and then you find \(a\). PS- what your motivation for posting so many problems (most of then difficult). It is hard to believe that all of them are homework sent by the teacher. |
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| Autor: | kinu [ 02 abr 2012, 16:00 ] |
| Título da Pergunta: | Re: Integer solution |
Thanks Ruhi Carpenter i have got 4 solution. actually it is not given by my teacher. actually it is a question given in my assignment sheet. so at first i have solve myself and if i have face difficulties then i post here for help Thanks |
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