03 jun 2016, 11:02
10^(x+1) + 10^(x-1) dividido por 10^(x-2)
03 jun 2016, 15:11
\(\frac{10^{(x+1)}+10^{(x-1)}}{10^{(x-2)}}=
\frac{10^{(x+1)}}{10^{(x-2)}}+\frac{10^{(x-1)}}{10^{(x-2)}}=
10^{[(x+1)-(x-2)]}+10^{[(x-1)-(x-2)]}=
10^3+10^1=
1010\)
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