02 dez 2015, 18:13
Se \(log_{27}Y-log_{27}X=\frac{1}{3}\), então, a relação entre x e y é dada por:
Alguem me ajuda?
02 dez 2015, 19:02
\(\log_{27}Y-\log_{27}X=\log_{27}{\frac{Y}{X}}=\frac{1}{3}\)
\(27^{\log_{27}{\frac{Y}{X}}}=27^{\frac{1}{3}}\)
\(\frac{Y}{X}=3\)
03 dez 2015, 14:59
log27y - log27x = 1/3
log27y/x = 1/3
271/3 = y/x
(33)1/3 = y/x
3 = y/x
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