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2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000

27 nov 2015, 14:13

2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000

Alguem pode me ajudar... pfv

Re: 2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000

28 nov 2015, 01:44

Rangel.gec Escreveu:2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000

Alguem pode me ajudar... pfv


log 4 + log 400 - (log 40000 + log 4000000)
log 1600 - log 160000000000
log (1600/16000000000)
log (1/100000000) = -8

Re: 2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000

28 nov 2015, 16:21

2 log 2+ 2 log 20 - 2 log 200 - 2 log 2000 =

2.(log 2 + log 2x10 - log 2x102 - log 2x103) =

2.[log 2 + (log 2 + log 10) - (log 2 + 2.log 10) - (log 2 + 3.log 10)] =

2.[log 2 + (log 2 + 1) - (log 2 + 2) - (log 2 + 3)] =

2.[log 2 + log 2 + 1 - log 2 - 2 - log 2 - 3] =

2.[log 2 + log 2 - log 2 - log 2 - 4] =

2.[2.log 2 - 2.log 2 - 4] =

2. -4 = -8
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