11 jan 2014, 15:17
Mostra que: \(1/2 - 2ln3=ln \sqrt{6}/9\)
11 jan 2014, 18:53
Veja que \(\ln (e^{\frac{1}{2}})=\frac{1}{2}\)
\(\ln(e^{\frac{1}{2}})-2*\ln(3)\)
\(\ln(e^{\frac{1}{2}})-\ln(3^{2})\)
\(\ln(e^{\frac{1}{2}})-\ln(9)\)
\(\ln(\frac{\sqrt e}{9})\)
Perceba que o gabarito está errado.
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