determine a derivada da questao abaixo
02 nov 2013, 01:08
\(y=\sqrt{3x+1}\)
Re: determine a derivada da questao abaixo [resolvida]
02 nov 2013, 01:37
Olá 
\(\\\\ y=\sqrt{3x+1} \\\\ y=(3x+1)^{\frac{1}{2}}\)
\(\text{Derivando:}\)
\(\\\\ y'=\frac{1}{2}*(3x+1)^{-\frac{1}{2}}*(3x+1)' \\\\ y'=\frac{3}{2*\sqrt{3x+1}}\)
\(\\\\ y=\sqrt{3x+1} \\\\ y=(3x+1)^{\frac{1}{2}}\)
\(\text{Derivando:}\)
\(\\\\ y'=\frac{1}{2}*(3x+1)^{-\frac{1}{2}}*(3x+1)' \\\\ y'=\frac{3}{2*\sqrt{3x+1}}\)