Coloque aqui todas as dúvidas que tiver sobre derivadas de funções de |R->|R, regras de derivadas e derivada da função inversa
31 Oct 2013, 02:47
determine a derivada
\(y= \sqrt{3x+1}\)
31 Oct 2013, 11:27
\(\sqrt{3x+1}=(3x+1)^{1/2}\)
Logo, a derivada é
\(1/2.(3x+1)^{-1/2}.(3x+1)'=\)
\(3/2.(3x+1)^{-1/2}.3\)
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