Fórum de Matemática
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Resolva as integrais definidas a seguir:

a)∫_0^(π/2)▒〖senx dx〗

b)∫_(π/2)^π▒〖cosx dx〗

\(\int_{0}^{\frac{\pi }{2}}\sin x \: dx=\left [ -\cos x \right ]_{0}^{\frac{\pi }{2}}=-(0-1)=1\)

\(\int_{\frac{\pi }{2}}^{\pi}\cos x \: dx=\left [ \sin x \right ]_{\frac{\pi }{2}}^{\pi}=0-1=-1\)