Fórum de Matemática
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Dúvida nesta questão:

\(\frac{\left [ \left ( 3^{\frac{1}{3}} \right )^{\frac{1}{2}} \times 3^{- \frac{1}{2}} \right ]}{3^2 \times 3^{- \frac{3}{2}}}\)

Obrigada.

\(\frac{\left [ \left ( 3^{\frac{1}{3}} \right )^{\frac{1}{2}} \times 3^{- \frac{1}{2}} \right ]}{3^2 \times 3^{- \frac{3}{2}}} =\)

\(\frac{3^{\left (\frac{1}{3} \times \frac{1}{2} \right )} \times 3^{- \frac{1}{2}}}{3^{\left ( 2 - \frac{3}{2} \right )}} =\)

\(\frac{3^{\frac{1}{6}} \times 3^{- \frac{1}{2}}}{3^{\frac{1}{2}}} =\)

\(\frac{3^\left ({\frac{1}{6} - \frac{1}{2}} \right )}{3^{\frac{1}{2}}} =\)

\(\frac{3^{- \frac{2}{6}}}{3^{\frac{1}{2}}} =\)

\(\frac{3^{- \frac{1}{3}}}{3^{\frac{1}{2}}} =\)

\(3^{\left ( - \frac{1}{3} - \frac{1}{2} \right )} =\)

\(\fbox{3^{- \frac{5}{6}}}\)

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Daniel Ferreira
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